BBjHttpRequest::getFileUpload

Description

In BBj 14.0 and higher, this method returns a BBjFileUpload object available in a BBjHttpRequest object.

Return Value	Method
BBjFileUpload	getFileUpload(string name)

Variable	Description
name	Specifies the name of the HTML form field element.

The example below demonstrates how to upload a file to a servlet and get the associated BBjFileUploadObject by name.

REM Obtain the instance of the BBjAPI object

LET myAPI!=BBjAPI()

MyServlet! = new MyServlet()

data!.setCallback(data!.ON_WEB_CONNECTION, myServlet!, "myMethod")

PROCESS_EVENTS

class public MyServlet

method public void myMethod(BBjServletEvent p_event!)

LET chan = UNT

request! = p_event!.getHttpRequest()

response! = p_event!.getHttpResponse()

resp!.setContentType("text/html")

open(chan)"JSERVLET"

print(chan)"<html><body><h1>Hello BBj!</h1>"

upload! = request!.getFileUpload("thefile")

if upload! <> null() then

declare BBjFileUpload uploadFile!

uploadFile! = cast(BBjFileUpload,upload!)

print(chan)"You uploaded '"

print(chan)uploadFile!.getOriginalName()

print(chan)"' of type:"+ uploadFile!.getContentType()

print(chan)" and Size:"

print(chan)uploadFile!.getContentLength()

print(chan)"bytes.<br>"

else

print(chan)"Please upload a file<br>"

print(chan)"<form id='upload' method='post' action='upload' enctype='multipart/form-data' >"